-(x^2)+180-8x=0

Solution for -(x^2)+180-8x=0 equation:

-(x^2)+180-8x=0

We add all the numbers together, and all the variables

-1x^2-8x+180=0

a = -1; b = -8; c = +180;
Δ = b2-4ac
Δ = -82-4·(-1)·180
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-28}{2*-1}=\frac{-20}{-2}
=+10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+28}{2*-1}=\frac{36}{-2}
=-18
$